Arrange the following reagents in the correct | vedclass

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(C) Step $1$: Cyclopentanone reacts with $KOD/D_2O$ (base-catalyzed deuterium exchange) to replace all $\alpha$-hydrogens with deuterium atoms,forming

Vedclass · Accepted Answer

$KOD/D_2O, LiAlH_4, H^{+}/ \Delta$

Vedclass · Answer

(C) Step $1$: Cyclopentanone reacts with $KOD/D_2O$ (base-catalyzed deuterium exchange) to replace all $\alpha$-hydrogens with deuterium atoms,forming $2,2,5,5$-tetradeuterocyclopentanone.Step $2$: The deuterated ketone is then reduced using $LiAlH_4$ to form the corresponding alcohol,$2,2,5,5$-tetradeuterocyclopentanol.Step $3$: Finally,acid-catalyzed dehydration $(H^{+}/ \Delta)$ of the alcohol leads to the formation of the alkene product,$1,5,5$-trideuterocyclopentene (note: the product structure in the image implies the elimination of $D_2O$ or $HOD$ to form the double bond).Therefore,the correct order is $KOD/D_2O, LiAlH_4, H^{+}/ \Delta$.

Arrange the following reagents in the correct order in which the above transformation is carried out:

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